fix(locale/shared): phrase-construction for strings without placeholders

string.gsub returns two variables, the updated string and the pattern occurrences.
The outer string.gsub would replace n occurrences, or nothing if the string did not
contain '%'.

imports/locale/shared.lua

@@ -31,7 +31,8 @@ function lib.loadLocale()
                 local locale = locales[var:sub(3, -2)]
 
                 if locale then
-                    v = v:gsub(var, locale:gsub('%%', '%%%%'))
+                    locale = locale:gsub('%%', '%%%%')
+                    v = v:gsub(var, locale)
                 end
             end
         end